Which one of the following is the correct set | vedclass

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(A, C) In $BeCl_2$,the central atom $Be$ has $2$ bond pairs and $0$ lone pairs,resulting in $sp$ hybridization and a linear shape. Thus,option $A$ is

Vedclass · Accepted Answer

$BCl_3, sp^2, 	ext{triangular planar}$

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(A, C) In $BeCl_2$,the central atom $Be$ has $2$ bond pairs and $0$ lone pairs,resulting in $sp$ hybridization and a linear shape. Thus,option $A$ is correct.In $BCl_3$,the central atom $B$ has $3$ bond pairs and $0$ lone pairs,resulting in $sp^2$ hybridization and a triangular planar shape. Thus,option $C$ is also correct.However,in standard multiple-choice questions of this type,both $A$ and $C$ are chemically accurate. Given the provided options,both $A$ and $C$ represent correct sets.

Molecule	Hybridisation of central atom	Shape
$(a)$ $PCl_5$	$dsp^3$	square pyramidal
$(b)$ $[Ni(CN)_4]^{2-}$	$sp^3$	tetrahedral
$(c)$ $SF_6$	$sp^3d^2$	octahedral
$(d)$ $IF_3$	$dsp^3$	pyramidal

Which one of the following is the correct set with respect to molecule,hybridization and shape?

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The hybridization states of the chlorine atom in $ClO_4^-$,$ClO_3^-$,and $ClO_2^-$ are respectively .....

Identify the correct set from the following table:
Molecule Hybridisation of central atom Shape
$(a)$ $PCl_5$ $dsp^3$ square pyramidal
$(b)$ $[Ni(CN)_4]^{2-}$ $sp^3$ tetrahedral
$(c)$ $SF_6$ $sp^3d^2$ octahedral
$(d)$ $IF_3$ $dsp^3$ pyramidal

Which of the following shows a linear structure?

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